p = Proc.new {|n| n } p.call(1) #ok, returns 1
#this is ok too def j(i) p = Proc.new {|n| return n; } p.call(i) end j(1) #ok - returns 1
#and ok with lambda p = lambda {|n| return n; } p(1) #ok, lambda lets caller stay in control
Jul 13, 2011
p = Proc.new {|n| n } p.call(1) #ok, returns 1
#this is ok too def j(i) p = Proc.new {|n| return n; } p.call(i) end j(1) #ok - returns 1
#and ok with lambda p = lambda {|n| return n; } p(1) #ok, lambda lets caller stay in control
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